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High-grade Ni-Cu-Pt-Pd-Au-Ag-Rh-Cr-V discoveries in the "Ring of Fire" NI 43-101 Update (March 2011): 11.0 Mt @ 1.78% Ni, 0.98% Cu, 0.99 gpt Pt and 3.41 gpt Pd and 0.20 gpt Au (M&I) / 9.0 Mt @ 1.10% Ni, 1.14% Cu, 1.16 gpt Pt and 3.49 gpt Pd and 0.30 gpt Au (Inf.)
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Re: Question for Hoov, Jackie79, Yixter or any other geos
Noront Resources
about 15 years ago
34
in response to Pivotal's message

You messed up the math a little bit there, my friend. There is no triangle with individual sides of lengths 1000, 176, and 1441.

For a maximum penetration of 1200 metres, set that as your hypotenuse. Dip angle is from horizontal, so theta in the equation is (90 minus dip).

Adjacent over hypotenuse = cosine theta, and you want to solve for the length of the adjacent side, which we'll call x.

x/1200 = cos (40) for a 50 degree dip

x = 1200 cos (40) = 919 metres

x/1200 cos (30) for a 60 degree dip

x= 1200 cos (30) = 1039 metres

Lar

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